Sisteme de ecuații cu 2 necunoscute (7)

1) $\begin{cases} 3x + 2y = 12 \\ 5x – 2y = 4 \end{cases}$

2)$\begin{cases} 2(x – 3) + 3y = 7 \\ 4x – (y + 1) = 11 \end{cases}$

3)$\begin{cases} x\sqrt{2} + y\sqrt{3} = 7\sqrt{2} + 2\sqrt{3} \\ 2x\sqrt{2} – 3y\sqrt{3} = 14\sqrt{2} – 6\sqrt{3} \end{cases}$

4)$\begin{cases} \frac{x}{2} + \frac{y}{3} = 4 \\ \frac{2x}{3} – \frac{y}{2} = 1 \end{cases}$

5)$\begin{cases} \frac{2}{x} + \frac{3}{y} = 7 \\ \frac{4}{x} – \frac{1}{y} = 0 \end{cases}$

6)$\begin{cases} |x| + 2|y| = 10 \\ 3|x| – |y| = 2 \end{cases}$

7)$\begin{cases} \frac{2x – 3y + 1}{2} + \frac{x + y}{3} = 2 \\ \frac{x – y – 1}{4} – \frac{2x + y}{2} = \frac{-7}{6} \end{cases}$

8)$\begin{cases} \frac{5}{x + 1} + \frac{2}{y – 2} = 4 \\ \frac{10}{x + 1} – \frac{1}{y – 2} = 3 \end{cases}$

9)$\begin{cases} |x – 5| + |y + 1| = 2 \\ 2|x – 5| + 3|y + 1| = 1 \end{cases}$

10)$\begin{cases} \sqrt{7 + 4\sqrt{3}} \cdot x + \sqrt{7 – 4\sqrt{3}} \cdot y = 4 \\ \sqrt{3 + 2\sqrt{2}} \cdot x – \sqrt{3 – 2\sqrt{2}} \cdot y = 2 \end{cases}$